An infinitely long straight conductor carries a current of $5 \,\mathrm{~A}$ as shown. An electron is moving with a speed of $10^{5} \, \mathrm{~m} / \mathrm{s}$ parallel to the conductor. The perpendicular distance between the electron and the conductor is $20 \, \mathrm{~cm}$ at an instant. Calculate the magnitude of the force experienced by the electron at that instant in $\times 10^{-20} \,N$
NEET 2021, Medium
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$B =\frac{\mu_{0} I}{2 \pi R}$
$F =B V q \sin \theta$
$\theta =90^{\circ}$
$F =B V q$
$F=\frac{\mu_{0} I}{2 \pi R} \times V \times e=\frac{2 \times 10^{-7} \times 5}{20 \times 10^{-2}} \times 10^{5} \times 1.6 \times 10^{-19}$
$F=8 \times 10^{-20}\, \mathrm{~N}$
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