Which of the following statement is correct? - Vidyadip

Question

Which of the following statement is correct?

✓

Answer

(c) : If optimal solution is obtained at two distinct points $A$ and $B$ (corners of the feasible region), then optimal solution is obtained at every point of segment $[A B]$.

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

More "M.C.Q (1 Marks)" from Linear Programming→Linear Programming — all question types→MATHS STD 12 Science question papers→Rajasthan Board STD 12 Science question papers→Rajasthan Board question paper generator→

Similar questions

if $\text{ax}+\frac{\text{b}}{\text{x}}\geq\text{c}$ for all positive x where a, b, > 0, then.

$\text{ab} < \frac{\text{c}^{2}}{4}$
$\text{ab} > \frac{\text{c}^{2}}{4}$
$\text{ab} > \frac{\text{c}}{4}$
$\text{None of these}$

The altitude of a cone is 20cm and its semi-vertical angle is 30°. If the semi-vertical angle is increasing at the rate of 2° per second, then the radius of the base is increasing at the rate of:

$30\text{cm}/\text{sec}.$
$\frac{160}{3}\text{cm}/\text{sec}.$
$10\text{cm}/\text{sec}.$
$160\text{cm}/\text{sec}.$

The area bounded by the curve $\text{y}=\sin\text{x}$ between the ordinates $\text{x}=0,\text{x}=\pi$ and the x-axis is:

$2\text{ sq. units}$
$4\text{ sq. units}$
$3\text{ sq. units}$
$1\text{ sq. units}$

The value of $\cos^{-1}\Big(\cos\frac{5\pi}{3}\Big)+\sin^{-1}\Big(\sin\frac{5\pi}{3}\Big)$ is:

$\frac{\pi}{2}$
$\frac{5\pi}{3}$
$\frac{10\pi}{3}$
$0$

A fair coin is tossed 99 times. If X is the number of times head appears, then P(X = r) is maximum when r is:

Find the value of $p$ for which the points $(−5, 1), (1, p)$ and $(4, −2)$ are collinear.

$\left|\begin{array}{cc}\cos \theta & -\sin \theta \\ \sin \theta & \cos \theta\end{array}\right|=$

(2, -3, -1) 2x - 3y + 6z + 7 = 0:

4
3
2
$\frac{1}{5}$

The value of objective function is maximum under linear constraints

Let $\text{f(x)}=\begin{cases}\frac{1}{|\text{x}|} & \text{for |x|}\geq1\\\text{ax}^2+\text{b} & \text{for |x|}<1\end{cases}$ if f(x) is continuous and differentiable at any point, then:

$\text{a}=\frac{1}{2},\text{b}=-\frac{3}{2}$
$\text{a}=-\frac{1}{2},\text{b}=\frac{3}{2}$
$\text{a}=1,\text{b}=-1$
None of these.