MCQ
Which of the following will produce a buffer solution when mixed in equal volumes?
  • A
    $0.1 \mathrm{~mol} \mathrm{dm}^{-3} \mathrm{NH}_4 \mathrm{OH}$ and $0.1 \mathrm{~mol} \mathrm{dm}^{-3} \mathrm{HCl}$.
  • B
    $0.05 \mathrm{~mol} \mathrm{dm}^{-3} \mathrm{NH}_4 \mathrm{OH}$ and $0.1 \mathrm{~mol} \mathrm{dm}^{-3} \mathrm{HCl}$.
  • $0.1 \mathrm{~mol} \mathrm{dm}^{-3} \mathrm{NH}_4 \mathrm{OH}$ and $0.05 \mathrm{~mol} \mathrm{dm}^{-3} \mathrm{HCl}$.
  • D
    $0.1 \mathrm{~mol} \mathrm{dm}^{-3} \mathrm{CH}_4 \mathrm{COONa}$ and $0.1 \mathrm{~mol} \mathrm{dm}^{-3} \mathrm{NaOH}$.

Answer

Correct option: C.
$0.1 \mathrm{~mol} \mathrm{dm}^{-3} \mathrm{NH}_4 \mathrm{OH}$ and $0.05 \mathrm{~mol} \mathrm{dm}^{-3} \mathrm{HCl}$.

In $(c)$, all $\text{HCl}$ will be neutralized and $\mathrm{NH}_4 \mathrm{Cl}$ will be formed. Also some $\mathrm{NH}_4 \mathrm{OH}$ will be left unneutralized. Thus, the final solution will contain $\mathrm{NH}_4 \mathrm{OH}$ and $\mathrm{NH}_4 \mathrm{Cl}$ and hence will form a buffer.

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