- A$\Delta V_{mix}$
- B$\Delta P = P_{observed} - P_{Raoult}$
- C$\Delta H_{mix}$
- ✓$\Delta S_{mix}$
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[Given $: h =6.626 \times 10^{-34}\,Js$,Mass of electron $=9.1 \times 10^{-31}$ ]
Product of the above reaction will be
$\mathrm{A}+\mathrm{B} \rightarrow \mathrm{C}$
$\text { rate }=\mathrm{k}[\mathrm{A}]^{1 / 2}[\mathrm{~B}]^{1 / 2}$
The reaction is initiated by taking $1 \mathrm{M}$ concentration $A$ and $B$ each. If the rate constant $(k)$ is $4.6 \times 10^{-2} \mathrm{~s}^{-1}$, then the time taken for $\mathrm{A}$ to become $0.1 \mathrm{M}$ is . . . . . . . . . . sec. (nearest integer)
$2Na(s) + 2HCl(g)\,\, \to \,\,2NaCl(s) + {H_2}(g),$$\Delta H = - 152\,kcal$ For the reaction $Na(s) + \frac{1}{2}C{l_2}(g)\,\, \to \,\,NaCl(s),\,\Delta H = $ .....$kcal$