i. Which one is more soluble in diethyl ether, anhydrous AlCl_3 o… - Vidyadip

Question

i. Which one is more soluble in diethyl ether, anhydrous $\mathrm{AlCl}_3$ or hydrated $\mathrm{AlCl}_3$ ? Explain in terms of bonding?
ii. Unlike ordinary fire, thermite reaction can not be stopped by pouring water. Explain.
iii. What happens when $\mathrm{B}_2 \mathrm{O}_3$ is heated with Mg ?

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Answer

i. Anhydrous $\mathrm{AlCl}_3$ is an electron deficient compound, therefore, more soluble in diethyl ether which donates a pair of electron whereas hydrated $\mathrm{AlCl}_3 \mathrm{AlCl}_3$ is not electron deficient due to donation of lone pair of electron by $\mathrm{H}_2 \mathrm{O}$.
ii. In therimate reaction $\mathrm{Fe}_2 \mathrm{O}_3$ supplies oxygen needed for reaction, therefore, cutting off supply of oxygen by water is not possible. At high temperature, 'Al' reacts with steam to form $\mathrm{H}_2$ which helps to spread fire.
iii. Boron metal is formed and MgO will be formed.
$\text{B}_2\text{O}_3\ +\ 3\text{Mg}\ \xrightarrow{\ \ \ \text{Heat}\ \ \ }\ 3\text{Mg}\ +\ 2\text{ B}$

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