Question
Which one is more soluble in diethyl ether, anhydrous $\mathrm{AlCl}_3$ or hydrated $\mathrm{AlCl}_3$ ? Explain in terms of bonding.
✓
Answer
Anhydrous $\mathrm{AlCl}_3$ is an electron-deficient compound while hydrated $\mathrm{AlCl}_3$ is not. Therefore, anhydrous $\mathrm{AlCl}_3$ is more soluble in diethyl ether because the oxygen atom of ether donates a pair of electrons to the vacant p-orbital on the Al atom in $\mathrm{AlCl}_3$ forming a coordinate bond.
In case of hydrated $\mathrm{AlCl}_3, \mathrm{Al}$ is not electron deficient since $\mathrm{H}_2 \mathrm{O}$ has already donated a pair of electrons to it.
In case of hydrated $\mathrm{AlCl}_3, \mathrm{Al}$ is not electron deficient since $\mathrm{H}_2 \mathrm{O}$ has already donated a pair of electrons to it.
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
What is the oxidation number of nitrogen atom in $N _3 H$ ?
→Complete the following chemical reactions : $\text{Ca}_3\text{N}_2(\text{s})+\text{H}_2\text{O}(\text{l})\xrightarrow{\ \ \ \ \ \ \ \ \ \ \ \ \ }$ Classify the above into $(a)$ hydrolysis, $(b)$ redox and $(c)$ hydration reactions.
→Why does boron resemble Si?
Define oxidation and reduction according to electronic concept.
Why group 2 elements (Mg and Ca) are harder and denser than group 1 elements?
What is the conjugate base of $\left[\mathrm{Fe}\left(\mathrm{H}_2 \mathrm{O}\right)_6\right]^{3+}$?
→At 1 atm will the $\Delta_{\mathrm{f}} \mathrm{H}^{\circ}$ be zero for $\mathrm{Cl}_2(\mathrm{g})$ and $\mathrm{Br}_2(\mathrm{g})$ ? Explain.
→Write the effect on radius, when value of $n$ on any atom is increased.
→Discuss the shape of the following molecules using the VSEPR model: $\mathrm{H}_2 \mathrm{S}$
→Considering the elements $\ce{F, Cl, O}$ and $N,$ the correct order of their chemical reactivity in terms of oxidizing property is :
→