MCQ
Which one of the following arrangements of molecules is correct on the basis of their dipole moments ?
  • A
    $BF_3 > NF_3 > NH_3$
  • B
    $NF_3 > BF_3 > NH_3$
  • C
    $NH_3 > BF_3 > NF_3$
  • $NH_3 > NF_3 > BF_3$

Answer

Correct option: D.
$NH_3 > NF_3 > BF_3$
d
In $NH _3$, charge from three bonds was moving towards nitrogen in the direction of lone pairs. In $NF _3$ and $BF _3$, due to structure, pyramidal and trigonal planar, $NF _3$ has more dipole moment. The resultant dipole for $BF _3$ is zero. Hence, the sequence is:

$BF _3\,<\, NF _3\,<\, NH _3$

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