MCQ
Which one of the following is expected to have largest size
- A${F^ - }$
- B${O^{ - 2}}$
- C$A{l^{ + 3}}$
- ✓${N^{ - 3}}$
${F^ - } = 9 + 1 = 10$ electrons ; ${O^{ - 2}} = 8 + 2 = 10$ electrons
$Al + 3 = 13 - 3 = 10$ electrons ; ${N^{3 - }} = 7 + 3 = 10\,{e^ - }.$
Because electrostatic force between nucleus and $\bar e$ cloud is least in nitrogen.
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.


$(i)$ Manganese exhibits $+7$ oxidation state in its oxide.
$(ii)$ Ruthenium and Osmium exhibit $+8$ oxidation in their oxides.
$(iii)$ $Sc$ shows $+4$ oxidation state which is oxidizing in nature.
$(iv)$ $Cr$ shows oxidising nature in $+6$ oxidation state.