Question
While analyzing an organic compound in Dumas' method, 0.30 grams of organic compound is obtained at 300 K temperature and 756 mm . At pressure 32.4 mm , nitrogen is obtained. Find percentage of nitrogen in compound.

Answer

$\frac{P_1 V_1}{T_1}=\frac{P_2 V_2}{T_2}$
Hence, volume of Nitrogen on S.T.P.
$
\begin{array}{l}
=\frac{P_1 \times V_1}{T_1} \times \frac{273}{760} mm \\
=\frac{756 \times 32.4}{300} \times \frac{273}{760} mm \\
=29.3 mm
\end{array}
$
$\begin{array}{l}\text { % of nitrogen in compound } \\ \qquad \begin{aligned} & =\frac{28}{22400} \times \frac{\text { Volume of } N _2 \text { on STP }}{\text { Weight of compound }} \times 100 \\ \quad & =\frac{28}{22400} \times \frac{29.3}{0.30} \times 100=12.20\end{aligned}\end{array}$

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