MCQ
White enamel of our teeth is
- A$C{a_3}{(P{O_4})_2}$
- ✓$Ca{F_2}$
- C$CaC{l_2}$
- D$CaB{r_2}$
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The end product in the above sequence is :
$C{O_2} + 2{H_2}O\, \rightleftharpoons {H_3}{O^ + } + HCO_3^ - $
for which the equilibrium constant is $3.8 \times 10^{-7}$ and $pH = 6.0$. The ratio of $[HCO_3^- ]$ to $[CO_2]$ would be :-
