- A$PbC{O_3}$
- B$PbC{O_3}.PbO$
- ✓$2PbC{O_3}.\,Pb{(OH)_2}$
- D$2PbS{O_4}.PbO$
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Assertion $A :$ Flourine forms one oxoacid.
Reason $R$ : Flourine has smallest size amongst all halogens and is highly electronegative
In the light of the above statements, choose the most appropriate answer from the options given below.

$\mathop {\begin{array}{*{20}{c}}
{\,\,\,\,\,\,\,C{H_3}}\\
|\\
{C{H_3} - C - OH}\\
|\\
{\,\,\,\,\,\,\,C{H_3}}
\end{array}}\limits_{\rm{I}} $ $\mathop {\begin{array}{*{20}{c}}
{\,\,\,\,\,\,\,C{H_3}}\\
|\\
{C{H_3} - CH - OH}
\end{array}}\limits_{{\rm{II}}} $ $\mathop {C{H_3} - C{H_2} - OH}\limits_{{\rm{III}}} $ $\mathop {\begin{array}{*{20}{c}}
{\,\,\,Ph}\\
|\\
{C{H_3} - C - OH}\\
|\\
{\,\,\,\,\,\,\,{\kern 1pt} C{H_3}}
\end{array}}\limits_{{\rm{IV}}} $
$MgO + 2HCl \longrightarrow MgCl_2 + H_2O$
