Question
Why are alkali metals always univalent? Why are they good reducing agents?

Answer

Alkali metals have largest atomic size, they can lose electrons easily therefore, they are good reducing agents. Secondly, they have low standard reduction potential. They are always univalent because after losing one electron, they acquire nearest noble gas configuration.

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Similar questions

Calculate the wavelength of the radiation which would cause photochemical dissociation of a chlorine molecule.
The bond dissociation energy $Cl - Cl$ of bond is $245 kJ mol ^{-1}$.
What will be the pH of a mixture of $\frac{ N }{10} HCl$
$
(100 ml)+\frac{N}{2} 20 HNO_3(200 ml)+\frac{M}{60} H_2 SO_4(300 ml) ?
$
The standard heat of formation of $\mathrm{CH}_4(\mathrm{~g}), \mathrm{CO}_2(\mathrm{~g})$ and $\mathrm{H}_2 \mathrm{O}(\mathrm{g})$ are $-76.2,-394.8$ and -241.6 kJ mol ${ }^{-1}$ respectively. Calculate the amount of heat evolved by burning $1 \mathrm{~m}^3$ of methane measured at NTP.
Calculate pH of 0.1 M solution of $HCOONH _4$, if $pK _{ a }$ of $HCOOH =3.6$ and $pK _{ b }$ of $NH _4 OH =4.8$.
Which is more informative? Empirical or molecular formula?
Write an expression of $\text{K}_c$ for the following reaction:
$\text{CaCO}_3(\text{s})\rightleftharpoons\text{CaO(s)}+\text{CO}_2(\text{g})$
What is the effect of increasing concentration of $\text{CO}_2$ on direction of reaction?
$\text{Hb(s)}+\text{O}_2\text{(g)}\rightleftharpoons\text{HbO}_2\text{(s)}$
Predict the direction in which equilibrium gets shifted it partial pressure of $\text{O}_2$ is lowered.
What are the atomic numbers of elements whose outermost electrons are represented by
  1. $3s^1$
  2. $2p^3$
  3. $3p^5$
Give the structure of alkyl halide which when treated with sodium metal in presence of ether gives $\left(\mathrm{CH}_3\right)_2 \mathrm{CH}-\mathrm{CH}\left(\mathrm{CH}_3\right)_2$.
Resonance structures of propenal are given below. Which of these resonating structures is more stable? Give reason for your answer.
$\text{CH}_2=\text{CH}-\text{CH}=\text{O}\leftrightarrow\stackrel{\oplus \ \ \ \ \ \ }{\text{CH}_2}-\text{CH}=\text{CH}-\stackrel{\ominus}{\text{O}}\\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \text{I}\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \text{II}$