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Equilibrium — Chemistry STD 11 Science — Question

Gujarat BoardEnglish MediumSTD 11 ScienceChemistryEquilibrium2 Marks
Question
Write an expression of $\text{K}_c$ for the following reaction:
$\text{CaCO}_3(\text{s})\rightleftharpoons\text{CaO(s)}+\text{CO}_2(\text{g})$
What is the effect of increasing concentration of $\text{CO}_2$ on direction of reaction?
✓

Answer

$\text{K}_{\text{c}}=[\text{CO}_2]$ $\because[\text{CaCO}_3(\text{s})]=1$The rate of backward reaction will increase with the increase in concentration of $\text{CO}_2$ because if we increase concentration of products, rate of backward reaction will increase.

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