Download App

The p-Block Elements — Chemistry STD 11 Science — Question

Gujarat BoardEnglish MediumSTD 11 ScienceChemistryThe p-Block Elements2 Marks
Question
Why does boron form stable electron deficient compounds?
✓

Answer

Boron has three valence electrons, it will share three electrons with other elements to form electron deficient compounds which are stable due to back bonding i.e. lone pair of electrons of halogen is denoted to vacant p-orbital of 'B' forming $\text{p}\pi-\text{p}\pi$ bond making it stable.

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

More "2 Marks Questions" from The p-Block Elements→The p-Block Elements — all question types→Chemistry STD 11 Science question papers→Gujarat Board STD 11 Science question papers→Gujarat Board question paper generator→

Similar questions

The aqueous solution of sugar does not conduct electricity. However, when sodium chloride is added to water, it conducts electricity. How will you explain this statement on the basis of ionisation and how is it affected by concentration of sodium chloride?
→
  1. Kidney stones are made up of which compound?
  2. Why do crystalline salts of Group 2 elements contain more water of crystallization than, Group 1 elements.
→
Name the compound in which :
(i) Oxidation number of oxygen is +2 .
(ii) Oxidation number of oxygen is +1 .
(iii) Oxidation number of chlorine is +1 .
→
In a reaction
$\mathrm{A}+\mathrm{B}_2 \rightarrow \mathrm{AB}_2$
Identify the limiting reagent, if any, in the following reaction mixtures.
$5 \mathrm{mol}\mathrm{~A}+2.5 \mathrm{~mol} \mathrm{~B}$.
→
What do you meant by standard enthalpy of reaction? Explain.
→
Differentiate between mass and weight.
→
An iron rod is immersed in solution containing 1.0M $NiSO_4$ and 1.0M $ZnSO_4.$ Predict giving reasons which of the following reactions is likely to proceed?
  1. Fe reduces $Zn^{2+}$ ions,
  2. Iron reduces $Ni^{2+}$​​​​​​​ ions.
Given,
$\text{E}^\circ_{\frac{\text{Zn}^{2+}}{\text{Zn}}}=-0.76\text{V, E}^{\circ}_{\frac{\text{Fe}^{2+}}{\text{Fe}}}=-0.44\text{V and }$
$\text{E}^\circ_{\frac{\text{Ni}^{2+}}{\text{Ni}}}=-0.25\text{V}$
→
Explain stock notation with example.
→
Give the Henderson's Hasselbalch equation for acidic buffer solution.
→
Compare the relative stability of the following species on the basis of molecular orbital theory and indicate their magnetic properties:
$\text{O}^+_2,\text{O}^-_2.$
→