Question
Why is $\mathrm{F}_2$ more reactive than $\mathrm{Cl}_2$ ?
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Answer
It is because $\mathrm{F}_2$ has lower bond dissociation enthalpy than $\mathrm{Cl}_2$ due to repulsion between valence electrons due to exceptionally small size of fluorine.
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${\left[\mathrm{SO}_2\right]=0.60 \mathrm{M},\left[\mathrm{O}_2\right]=0.82 \mathrm{M} \text { and }\left[\mathrm{SO}_3\right]=1.90 \mathrm{M} ?}$
$2 \mathrm{SO}_{2(\mathrm{~g})}+\mathrm{O}_{2(\mathrm{~g})} \rightleftharpoons 2 \mathrm{SO}_{3(\mathrm{~g})}$
→${\left[\mathrm{SO}_2\right]=0.60 \mathrm{M},\left[\mathrm{O}_2\right]=0.82 \mathrm{M} \text { and }\left[\mathrm{SO}_3\right]=1.90 \mathrm{M} ?}$
$2 \mathrm{SO}_{2(\mathrm{~g})}+\mathrm{O}_{2(\mathrm{~g})} \rightleftharpoons 2 \mathrm{SO}_{3(\mathrm{~g})}$