Question
Why molecularity is applicable only for elementary reactions and order is applicable for elementary as well as complex reactions?
✓
Answer
A complex reaction occurs through several elementary reactions. Numbers of molecules involved in each elementary reaction may be different i.e., the molecularity of each step may be different. Therefore, the molecularity of overall complex reaction is meaningless. On the other hand, order of a complex reaction is experimentally determined by the slowest step in its mechanism and is therefore, applicable even in the case of complex reactions.
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
Explain the following terms giving a suitable example in each case:
- Ambident ligand.
- Denticity of a ligand.
- Crystal field splitting in an octahedral field.
Give the structures of A and B in the following sequence of reactions:
→- $\text{CH}_3\text{COOH}\xrightarrow[\Delta]{\text{NH}_3\ \ \ }\text{A}\ \ \ \xrightarrow{\text{NaOBr}}\text{B}$
- $\text{C}_6\text{H}_5\text{No}_2\xrightarrow{\text{Fe}/ \text{ HCl}}\text{A}\ \ \ \ \ \xrightarrow[0^\circ-5^\circ\text{C}]{\text{NaNo}_2+\text{HCl}}\text{B}$
- $\text{C}_6\text{H}_5\text{N}_2^+\text{Cl}^{-}\xrightarrow[\Delta]{\text{CuCN}}\text{A}\ \ \ \ \xrightarrow{\text{H}_2\text{O}/\text{ H}^+}\text{B}$
Write the IUPAC name of the ionisation isomer of the coordination compound [Co(NH3)5Br]SO4. Give one chemical test to distinguish between the two compounds.
Why transition elements form a coloured ions?
Following reaction takes place in one step:
$\text{2NO(g)+O}_2\text{(g)}\rightarrow\text{2NO}_2\text{(g)}$
How will the rate of the above reaction change if the volume of the reaction vessel is reduced to one-third of its original volume? Will there be any change in the order of the reaction with reduced volume?
→$\text{2NO(g)+O}_2\text{(g)}\rightarrow\text{2NO}_2\text{(g)}$
How will the rate of the above reaction change if the volume of the reaction vessel is reduced to one-third of its original volume? Will there be any change in the order of the reaction with reduced volume?
How many molecules of chlorine should be deposited from molten sodium chloride in one minute by a current of 300 milliampere?
What is azeotropes? Explain it's Types.
For a reaction $\text{A + B}\xrightarrow{\ \ \ \ \ }\text{Products},$ the rate law is - $\text{Rate}=\text{k}[\text{A}][\text{B}]^\frac{3}{2}$ Can the reaction be an elementary reaction? Explain.
→
Calculate the potential for half-cell containing
0.10M K2Cr2O7 (aq), 0.20M Cr3+(aq) and 1.0 × 10-4M H+(aq). The half cell reaction is
$\text{Cr}_2\text{O}_7^{2-}(\text{aq})14\text{H}^+(\text{aq})+6\text{e}^-\xrightarrow{ \ \ \ \ \ \ \ \ \ \ }2\text{Cr}^{3+}(\text{aq})+7\text{H}_2\text{O}(\text{l})$
and the standard electrode potential is given as E° = 1.33V.
→0.10M K2Cr2O7 (aq), 0.20M Cr3+(aq) and 1.0 × 10-4M H+(aq). The half cell reaction is
$\text{Cr}_2\text{O}_7^{2-}(\text{aq})14\text{H}^+(\text{aq})+6\text{e}^-\xrightarrow{ \ \ \ \ \ \ \ \ \ \ }2\text{Cr}^{3+}(\text{aq})+7\text{H}_2\text{O}(\text{l})$
and the standard electrode potential is given as E° = 1.33V.