Question
Why nobelium is the only actinoid with $+2$ oxidation state?

Answer

  • Nobelium has the electronic configuration ${ }_{102} NO :[ Rn ] 5 f^{14} 6 d^{\circ} 7 s^2$
  • $No ^{2+}$ : [Rn] $5 f^{14} 6 d^{\circ}$
  • Since the $4$ f subshell is completely filled and $6 d^{\circ}$ empty, $+2$ oxidation state is the stable oxidation state.
  • Other actinoids in $+ 2$ oxidation state are not as stable due to incomplete $4f$ subshell.

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