MCQ
With respect to a rectangular cartesian coordinate system, three vectors are expressed as $\vec{a}=4 \hat{i}-\hat{j}, \vec{b}=-3 \hat{i}+2 \hat{j}$ and $\vec{c}=-\hat{k}$ where $\hat{i}, \hat{j}, \hat{k}$ are unit vectors, along the $X, Y$ and $Z$-axis respectively. The unit vectors $\hat{r}$ along the direction of sum of these vector is
  • $\hat{r}=\frac{1}{\sqrt{3}}(\hat{i}+\hat{j}-\hat{k})$
  • B
    $\hat{r}=\frac{1}{\sqrt{2}}(\hat{i}+\hat{j}-\hat{k})$
  • C
    $\hat{r}=\frac{1}{3}(\hat{i}-\hat{j}+\hat{k})$
  • D
    $\hat{r}=\frac{1}{\sqrt{2}}(\hat{i}+\hat{j}+\hat{k})$

Answer

Correct option: A.
$\hat{r}=\frac{1}{\sqrt{3}}(\hat{i}+\hat{j}-\hat{k})$
(a)$\begin{aligned}& \vec{r}=\vec{a}+\vec{b}+\vec{c}=4 \hat{i}-\hat{j}-3 \hat{i +2\hat{j}-\hat{k}=\hat{i}+\hat{j}-\hat{k} \\& \hat{r}=\frac{\vec{r}}{|r|}=\frac{\hat{i}\hat{j}-\hat{k}}{\sqrt{1^2+1^2+(-1)^2}}=\frac{\hat{i}+\hat{j}-\hat{k}}{\sqrt{3}}\end{aligned}$

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