With rise in temperature, density of a given body changes according to one of the following relations
Medium
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(b)Since, with increase in temperature, volume of given body increases, while mass remains constant so that density will decrease.
i.e. $\frac{\rho }{{{\rho _0}}} = \frac{{m/V}}{{m/{V_0}}} = \frac{{{V_0}}}{V} = \frac{{{V_0}}}{{{V_0}(1 + r\Delta \theta )}} = (1 - \gamma \Delta \theta )$
$\rho = {\rho _0}(1 - \gamma \Delta \theta )$
i.e. $\frac{\rho }{{{\rho _0}}} = \frac{{m/V}}{{m/{V_0}}} = \frac{{{V_0}}}{V} = \frac{{{V_0}}}{{{V_0}(1 + r\Delta \theta )}} = (1 - \gamma \Delta \theta )$
$\rho = {\rho _0}(1 - \gamma \Delta \theta )$
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