MCQ
With what minimum acceleration can a fireman slides down a rope while breaking strength of the rope is $\frac{2}{3}$ of his weight
- A$\frac{2}{3} g$
- B$\frac{4}{3} g$
- ✓$\frac{1}{3} g$
- DZero
✓
Answer
Correct option: C.
$\frac{1}{3} g$
If man slides down with some acceleration then its apparent weight decreases.
Forcritical condition rope can bear only $2 / 3$ of his weight.If $(a)$ is the minimum acceleration then,Tension in the rope $=m(g-a)=$ Breaking strength $\Rightarrow m(ga)=\frac{2}{3}mg\Rightarrow a=g\frac{2 g}{3}=\frac{g}{3}$
Forcritical condition rope can bear only $2 / 3$ of his weight.If $(a)$ is the minimum acceleration then,Tension in the rope $=m(g-a)=$ Breaking strength $\Rightarrow m(ga)=\frac{2}{3}mg\Rightarrow a=g\frac{2 g}{3}=\frac{g}{3}$
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