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Motion in One Dimension — JEE physics STD 12 Science — Question

CBSE BoardEnglish MediumSTD 12 ScienceJEE physicsMotion in One Dimension1 Mark
MCQ
With what velocity a ball be projected vertically so that the distance covered by it in $5^{-}$second is twice the distance it covers in its 6 second $\left(g=10 m / s^2\right)$
  • A
    $58.8 m / s$
  • B
    $49 m / s$
  • ✓
    $65 m / s$
  • D
    $19.6 m / s$
✓

Answer

Correct option: C.
$65 m / s$
(c)
$h_{n^{\text {min }}}=u-\frac{g}{2}(2 n-1)$
$  h_{5^{\text{th}}}=u - \frac{10}{2}(2 \times 5-1)=u-45 $
$h_{6^{th}}=u-\frac{10}{2}(2 \times 6-1)=u-55$
Given $h_{5^{\text {th }}}=2 \times h_{6^{\text {th }}}$.
By solving we get $u=65\mathrm{~m} / \mathrm{s}$

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