Question
Without using Pythagoras theorem, show that the points A(0, 4), B(1, 2) and C(3, 3) are the vertices of a right angled triangle.

Answer

Slope of $\text{AB}=\frac{2-4}{1-0}=-2$ Slope of $\text{BC}=\frac{3-2}{3-1}=\frac{1}{2}$ slope of AB × slope of BC $=-2\times\frac{1}{2}=-1$ $\therefore$ Anlgle between AB and BC $=\frac{\pi}{2}$ $\therefore$ ABC are the vertices of a right angled triangle.

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