Question
Work out the surface area of following shape (use $\pi$ = $3.14$).
✓
Answer
In the given figure, there are two cuboides are joined.
$\therefore$ Total surface area of the given solid
$= 2(24 \times 12 + 12 \times 12 + 12 \times 24) +2(12 \times 12 + 12 \times 12 + 12 \times 12) - 2(12 \times 12)$
$= 1440 + 864 - 288$
$= 2016cm^2$
$\therefore$ Total surface area of the given solid
$= 2(24 \times 12 + 12 \times 12 + 12 \times 24) +2(12 \times 12 + 12 \times 12 + 12 \times 12) - 2(12 \times 12)$
$= 1440 + 864 - 288$
$= 2016cm^2$
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