Question
Write a pythagorean triplet whose smallest member is: $14$
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Answer
For every natural number $m>1,\left(2 m, m^2-1, m^2+1\right)$ is a Pythagorean triplet.
Putting $2m = 14,$
We get $m = 7$
Thus, we get the triplet $(14, 48, 50).$
Putting $2m = 14,$
We get $m = 7$
Thus, we get the triplet $(14, 48, 50).$
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