Question
Write an acceleration in terms of its component?###Show that the acceleration is the second derivative of position vector with respect to time.

Answer

in terms of components, we can write,
$\vec{a}=\frac{d v_x}{d t} \hat{i}+\frac{d v_y}{d t} \hat{j}+\frac{d v_z}{d t} \hat{k}=\frac{d \vec{v}}{d t}$
$a_x=\frac{d^2 x}{d t^2}, a_y=\frac{d^2 y}{d t^2}, a_z=\frac{d^2 z}{d t^2}$
are the components of instantaneous acceleration. Since each component of velocity is the derivative of the corresponding coordinate, we can express the components $a _{ x ^{\prime}} a _{ y ^{\prime}}$ and $a _{ z }$ as $a_x=\frac{d v_x}{d t}, a_y=\frac{d v_y}{d t}, a_z=\frac{d v_z}{d t}$
Then the acceleration vector $\vec{a}$ it self is
$\vec{a}=\frac{d^2 x}{d t^2} \hat{i}+\frac{d^2 y}{d t^2} \hat{j}+\frac{d^2 z}{d t^2} \hat{k}=\frac{d^2 \vec{r}}{d t^2}$
Thus acceleration is the second derivative of position vector with respect to time.

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