MCQ
Write $\cot ^{-1}\left(\frac{1}{\sqrt{x^{2}-1}}\right), x>1$ in the simplest form.
- ✓$\sec ^{-1} x$
- B$cosec ^{-1} x$
- C$tan ^{-1} x$
- D$cot ^{-1} x$
Therefore, $\cot ^{-1} \frac{1}{\sqrt{x^{2}-1}}=\cot ^{-1}(\cot \theta)$$=\theta=\sec ^{-1} x$
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If matrix A = [aij]2×2, where aij = 1, if $\text{i}\neq\text{j}$ and 0 if i = j then A2 equal to: