Question
Write first four terms of the $AP$, when the first term $a = -1.25$ and the common difference, $d = –0.25$
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Answer
Here, $a_1=a=-1.25, d=-0.25$
First term, $a =-1.25$
Second term, $a_2=-1.25+d=-1.25+(-0.25)=-1.50$
Third term $=-1.50+d=-1.50+(-0.25)=-1.75$
Fourth term $=-1.75+d=-1.75+(-0.25)=-2.00$
Hence, first four terms of the given AP are $-1.25,-1.75,-2.00$
First term, $a =-1.25$
Second term, $a_2=-1.25+d=-1.25+(-0.25)=-1.50$
Third term $=-1.50+d=-1.50+(-0.25)=-1.75$
Fourth term $=-1.75+d=-1.75+(-0.25)=-2.00$
Hence, first four terms of the given AP are $-1.25,-1.75,-2.00$
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