Question
Write in ascending order $: 3\sqrt5$ and $4\sqrt3$

Answer

$ 3 \sqrt{5}=\sqrt{3^2 \times 5}=\sqrt{45}$
$,4 \sqrt{3}=\sqrt{4^2 \times 3}=\sqrt{48}$
and $45 < 48$
$ \therefore \sqrt{45} < \sqrt{48}$
$\Rightarrow 3 \sqrt{5} < 4 \sqrt{3}$

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