Write Nernst equation for single electrode potential.

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Answer

For the electrode reaction $\text{M}^{\text{n}+}+\text{ne}^-\xrightarrow{ \ \ \ \ \ }\text{M}$
$\frac{\text{E}_{\text{M}^{\text{n}+}}}{\text{M}}=\frac{\text{E}^{\circ}_{\text{M}^{\text{n}+}}}{\text{M}}-\frac{2.303\text{RT}}{\text{nF}}\log\frac{|\text{M}|}{|\text{M}^{\text{n}+}|}$
$=\frac{\text{E}^{\circ}_{\text{M}^{\text{n}+}}}{\text{M}}-\frac{2.303\text{RT}}{\text{nF}}\log\frac{1}{|\text{M}^{\text{n}+}|}$

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