Question
Write reactions involved in the formation of Teflon
✓
Answer
Teflon is polytetrafluoroethylene. The monomer used in preparation of teflon is tetrafluoroethylene, $(CF_2 = CF_2)$ which is a gas at room temperature. Tetrafluoroethylene is polymerized by using free radical initiators such as hydrogen peroxide or ammonium persulphate at high pressure.
Properties:
- Telflon is tough, chemically inert and resistant to heat and attack by corrosive reagents.
- C – F bond is very difficult to break and remains unaffected by corrosive alkali, organic solvents.
Uses : Telflon is used in making non-stick cookware, oil seals, gaskets, etc.
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
How is phenol (carbolic acid) prepared from aniline (diazotization)?###How is carbolic acid prepared from amino benzene?
A first order reaction takes 40 minutes for 30% decomposition. Calculate its half life. (77.66 min)
What is esterificatlon? how Is an ester obtained from alcohol or phenol?
What is the action of hot and concentrated sulphuric acid on the following :
(i) Carbon
(ii) Sulphur
(iii) Phosphorus
(iv) Zn
(v) Cu
(vi) Haloacid (HX)?
(i) Carbon
(ii) Sulphur
(iii) Phosphorus
(iv) Zn
(v) Cu
(vi) Haloacid (HX)?
Sucrose decomposes in acid solution to give glucose and fructose according to the first order rate law.
The half life of the reaction is $3$ hours. Calculate fraction of sucrose which will remain after $8$ hours.
→The half life of the reaction is $3$ hours. Calculate fraction of sucrose which will remain after $8$ hours.
The rate of the reaction $2 A+B \rightarrow 2 C+D$ is $6 \times 10^{-4} mol dm ^{-3} s^{-1}$ when $[A]=[B]=0.3 mol dm ^{-3}$ If the reaction is of first order in $A$ and zeroth order in $B$ , what is the rate constant?
→Write ozonolysis reaction for
(1) Propylene and
(2) Isobutylene.
(1) Propylene and
(2) Isobutylene.
State Disadvantages of nanoparticles and nanotechnology.
What is meant by conjugate acid-base pair?
Identify 'A', 'B' and 'C' in following chain reaction and rewrite the chemical reactions:
$CH _3 CH _2 OH \xrightarrow[B r_2]{ red \cdot P ^{\prime}} A \xrightarrow[\text { alc }]{ KCN } B \xrightarrow[\text { Ether }]{ LiAlH _4} C$
→$CH _3 CH _2 OH \xrightarrow[B r_2]{ red \cdot P ^{\prime}} A \xrightarrow[\text { alc }]{ KCN } B \xrightarrow[\text { Ether }]{ LiAlH _4} C$