Write symbolically the nuclear $\beta^{+}$decay process of $^{11}_{6}\text{C}$ . Is the decayed product X an isotope or isobar of $^{11}_{6}\text{C}$?
Given the mass values m $(^{11}_{6}\text{C})$ = 11·011434 u and m (X) = 11·009305 u. Estimate the Q-value in this process.
Given the mass values m $(^{11}_{6}\text{C})$ = 11·011434 u and m (X) = 11·009305 u. Estimate the Q-value in this process.
CBSE OUTSIDE DELHI - SET 3 PANCHKULA 2015
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Equation $^{11}_{6}\text{C}\rightarrow^{11}_{5}\text{X} + \text{i}^{e} + \text{v} + \text{Q}$
(? ?? ? on the R.H.S.)
X is an isobar
Mass defect $(\Delta\text{m}) = \text{m}(^{11}_{6}\text{C}) - \text{m}(^{11}_{5}\text{X})$
$ = ( 11.011434 - 11.009305) \text{u}$
$ = 0.002129\text{u}$
$\text{Q} = \Delta\text{m}\times931.5\text{ MeV}$
$=0.002129\times931.5 \text{ MeV}$
$ = 1.98\text{ MeV}$.
(? ?? ? on the R.H.S.)
X is an isobar
Mass defect $(\Delta\text{m}) = \text{m}(^{11}_{6}\text{C}) - \text{m}(^{11}_{5}\text{X})$
$ = ( 11.011434 - 11.009305) \text{u}$
$ = 0.002129\text{u}$
$\text{Q} = \Delta\text{m}\times931.5\text{ MeV}$
$=0.002129\times931.5 \text{ MeV}$
$ = 1.98\text{ MeV}$.
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