MCQ
Write the correct answer in the following: In a frequency distribution, the mid value of a class is $10$ and the width of the class is. The lower limit of the class is:
- A$6$
- ✓$7$
- C$8$
- D$12$
✓
Answer
Correct option: B.
$7$
Let $x$ and $y$ be the uppel and lower and lower class limit in a frequency distribution.
Now, mid value of a class $\frac{(\text{x}+\text{y})}{2}=10$ [given]
$\Rightarrow x + y = 20 ...(i)$
Also, given that, width of class$ x - y = 6 ...(ii)$
On adding Eqs. $(i)$ and $(ii)$, we get
$2x = 20 + 6$
$\Rightarrow 2x = 26$
$\Rightarrow x = 13$
On putting $x = 13$ in Eq. $(i)$, we get
$13 + y = 20$
$\Rightarrow y = 7$
Hence, the lower limit of the class is $7$.
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