Answer

  1. (-2, 4)
    Solution:
    Here, given point P lies in II quadrant, so its abscissa will be negative and ordinate will be positive. Also its perpendicular distance from X-axis is 4 y-coordinate of P is 4 and its perpendicular distance from Y-axis is 2. So, x–coordinate is -2. Hence, coordinate of P are (-2, 4).

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