MCQ
Write the correct answer in the following: Point $(-3, 5)$ lies in the:
- AFirst quadrant.
- ✓Second quadrant.
- CThird quadrant.
- DFourth quadrant.
✓
Answer
Correct option: B.
Second quadrant.
In the point $(-3, 5)$ abscissa is negative and ordinate is positive. So, it lies in the second quadrant.
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
If $x + 3$ is a factor of $x^2 - ax - 15, $ then $a =$
→$ABCD$ is a parallelogram and $E$ and $F$ are the centroids of triangles $ABD$ and $BCD$ respectively, then $EF =$
→If $\text{x}=\frac{\sqrt{7}}{5}$ and $\frac{5}{\text{x}}=\text{p}\sqrt{7}$ then the value of $p$ is:
→The given figures show two congruent circles with centre $O$ and $O’$. Arc $AXB$ subtends an angle of $75^\circ$ at the centre and arc $A’YB’$ subtends an angle of $25^\circ $ at the centre $O’.$ Then, the ratio of arcs $AXB$ to $A ‘YB’$ is:
→If $\sqrt{5}=2.236,$ then $\frac{1}{\sqrt{5}}.$
→$\frac{(a-b)^3-(a+b)^3}{2}+a\left(a^2+3 b^2\right)=$
→The value of $\frac{(0.013)^3+(0.007)^3}{(0.013)^2-0.013\times0.007+(0.007)^2},$ is:
→The coefficient of $x^3$ in $2 x+x^2-5 x^3+x^4$ is:
→If $\bar{\text{x}}$ is the mean of $x_1, x_2, \ldots, x_n$ then for $\text{a}\neq0,$ the mean $ax, ax_2, ..., axn,\frac{\text{x}_1}{\text{a}},\frac{\text{x}_2}{\text{a}},\ \dots,\frac{\text{x}_\text{n}}{\text{a}}$ is:
→In a $\triangle\text{ABC}, \ \angle\text{A} = 50^\circ$ and $BC$ is produced to a point $D$. If the bisectors $\angle\text{ACD}$ meet at $E$, then $\angle\text{E} =$
→