MCQ
Write the correct answer in the following: The width of five continuous classes in a frequency distribution is $5$ and the lower class-limit of the lowest class is $10.$ The upper class-limit of the highest class is:
- A$15$
- B$25$
- ✓$35$
- D$40$
Sol. Width of each of the five continuous classes in a frequency distribution is $5.$
Lower class limit of the lowest class $= 10$
Upper class limit of the lowest class is $10 + 5 = 15$
So, the five continuous classes are
$10 - 15, 15 - 20, 20 - 25, 25 - 30, 30 - 35$
Hence, the upper-class limit of the height class is $35.$
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