MCQ
- A20°
- B40°
- C60°
- D10°
✓
Answer
- 40°.
Solution:
Given, $\angle\text{ABC} = 20^\circ$
We know that, angle subtended at the centre by an arc is twice the angle subtended by it at the remaining part of circle.
$\angle\text{AOC} = 2\angle\text{ABC} = 2 \times 20^\circ = 40^\circ$
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