Question
Write the expression for equilibrium constant $K_p$ for the reaction:
$3\text{Fe(s)}+\text{4H}_2\text{O(g)}\rightleftharpoons\text{Fe}_3\text{O}_4(\text{s})+4\text{H}_2(\text{g})$

Answer

$\mathrm{K}_{\mathrm{p}}=\frac{\left(\mathrm{pH}_2\right)^4}{\left(\mathrm{pH}_2 \mathrm{O}\right)}\left[\mathrm{Fe}\right.$ and $\mathrm{Fe}_3 \mathrm{O}_4$ are pure solids]
$[\mathrm{Fe}(\mathrm{s})]=\left[\mathrm{Fe}_3 \mathrm{O}_4(\mathrm{~s})\right]=1$.

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