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Equilibrium — Chemistry STD 11 Science — Question

Gujarat BoardEnglish MediumSTD 11 ScienceChemistryEquilibrium1 Mark
Question
Write the expression for the equilibrium constant ($\text{K}_{\text{c}}$) for the reaction:
$\text{CH}_3\text{COOC}_2\text{H}_5(\text{aq})+\text{H}_2\text{O(l)}\\\rightleftharpoons\text{CH}_3\text{COOH}
(\text{aq})+\text{C}_2\text{H}_5\text{OH}(\text{aq})$
✓

Answer

$\text{K}_{\text{c}}=\frac{[\text{CH}_3\text{COOH}][\text{C}_2\text{H}_5\text{OH}]}{[\text{CH}_3\text{COOC}_2\text{H}_2\text{H}_5][\text{H}_2\text{O}]}$

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