Question
Write the following as decimals:
$23+\frac{2}{10}+\frac{6}{1000}$
$23+\frac{2}{10}+\frac{6}{1000}$
✓
Answer
$23+\frac{2}{10}+\frac{6}{1000}$
Convert $\frac{2}{10}$ and $\frac{6}{1000}$ into decimals,
$\frac{2}{10}$
Mark the decimal point one place from right to left,
$\frac{2}{10}$
$=0.2$
Mark the decimal point three places from right to left,
$\frac{6}{1000}$
$=0.006$
23, 0.2, 0.006 are unlike decimals. So, we convert them into like decimals.
$=23+\frac{2}{10}+\frac{6}{1000}$
$=23+0.2+0.006$
$=23.206$
Convert $\frac{2}{10}$ and $\frac{6}{1000}$ into decimals,
$\frac{2}{10}$
Mark the decimal point one place from right to left,
$\frac{2}{10}$
$=0.2$
Mark the decimal point three places from right to left,
$\frac{6}{1000}$
$=0.006$
23, 0.2, 0.006 are unlike decimals. So, we convert them into like decimals.
$=23+\frac{2}{10}+\frac{6}{1000}$
$=23+0.2+0.006$
$=23.206$
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
Waht should be added to $5\frac{3}{7}$ to get 12?
→$\text{x}-\frac35=\frac75$
→lf milk is avaitabte at $₹\ 17\frac{3}{4}$ per litre, find the cost of $7\frac{2}{5}$ litres of milk.
→A boy is cycling such that the wheels of the cycle are making 140 revolutions per minute. If the diameter of the wheel is 60cm, calculate the speed per hour with which the boy is cycling.
1152 bars of soap can be packed in 8 cartons of the same size. How many such cartons will be required to pack 3888 bars?
Reema took a loan of Rs. 8000 from a money lender, who charged interest at the rate of 18% per annum. After 2 years, Reema paid him Rs. 10400 and wristwatch to clear the debt. What is the price of the watch?
Find the time when:
Principal = Rs. 6400, S.I. = Rs. 1152 and rate = 6% p.a.
Principal = Rs. 6400, S.I. = Rs. 1152 and rate = 6% p.a.
Find the sum:
$3\frac{4}{5}+2\frac{13}{10}+1\frac{1}{15}$
→$3\frac{4}{5}+2\frac{13}{10}+1\frac{1}{15}$
In each of the given figures, two lines/ and m are cut by a transevrsal t. Find whether $\text{l || m}.$
→The hypotenuse of a right triangle is 26cm long. If one of the remaining two sides is 10cm long, find the length of the other side.