Question
Write the given rational numbers in ascending order.$\frac{-3}{7}, \frac{-3}{2}, \frac{-3}{4}$
✓
Answer
We need to make the denominators the same by taking the $LCM$ of $7,2 \& 4$
$LCM$ of $7,2 \& 4$ is $28$
$\frac{-3}{7}, \frac{-3}{2}, \frac{-3}{4}$
$\frac{-3}{7}=\frac{-3 \times 4}{7 \times 4}=\frac{-12}{28}$
$\frac{-3}{2}=\frac{-3 \times 14}{2 \times 14}=\frac{-42}{28}$
$\frac{-3}{4}=\frac{-3 \times 7}{4 \times 7}=\frac{-21}{28}$
$\because$$\frac{-42}{28}<-\frac{21}{28}<-\frac{12}{28}$
$-\frac{3}{2}<-\frac{3}{4}<-\frac{3}{7}$
$LCM$ of $7,2 \& 4$ is $28$
$\frac{-3}{7}, \frac{-3}{2}, \frac{-3}{4}$
$\frac{-3}{7}=\frac{-3 \times 4}{7 \times 4}=\frac{-12}{28}$
$\frac{-3}{2}=\frac{-3 \times 14}{2 \times 14}=\frac{-42}{28}$
$\frac{-3}{4}=\frac{-3 \times 7}{4 \times 7}=\frac{-21}{28}$
$\because$$\frac{-42}{28}<-\frac{21}{28}<-\frac{12}{28}$
$-\frac{3}{2}<-\frac{3}{4}<-\frac{3}{7}$
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