Write the isomers of the compound having formula $\ce{C_4H_9Br}.$
Download our app for free and get started
There is four isomers of the given compound.
- $\text{CH}_3\text{CH}_2\text{CH}_2\text{CH}_2\text{Br}$
- $\ \ \ \ \ \ \ \ \ \ \ \ \ \text{CH}_3\\ \\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ |\\\text{CH}_3-\text{CH}-\text{CH}_2\text{Br}$
- $\ \ \ \ \ \ \ \ \ \ \ \ \ \text{CH}_3\\ \\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ |\\\text{CH}_3-\text{C}-\text{Br}\\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ |\\ \ \ \ \ \ \ \ \ \ \ \ \ \ \text{CH}_3$
- $\text{CH}_3\text{CH}_2\text{CH}\text{Br}\text{CH}_3$
Download our appand get started for free
Experience the future of education. Simply download our apps or reach out to us for more information. Let's shape the future of learning together!No signup needed.*
Similar Questions
- 1Give the $\ce{IUPAC}$ names of the following compound: $\ce{CH_3CH(Cl)CH(Br)CH_3}$View Solution
- 2Write the structure of $1-$Bromo$-4-$chlorobut$-2-$ene.View Solution
- 3View SolutionHow will you bring about the following conversion?
Ethanol to ethyl fluoride. - 4View SolutionHow will you bring about the following conversion?
Propene to 1-nitropropane. - 5Arrange the compounds of each set in order of reactivity towards $S_N2$ displacement: $1-$Bromobutane, $1-$Bromo$-2,2-$dimethylpropane, $1-$Bromo$-2-$methylbutane, $1-$Bromo$-3-$methylbutane.View Solution
- 6View SolutionHow will you bring about the following conversion?
Propene to propyne. - 7View SolutionHalogen compounds used in industry as solvents are alkyl chlorides rather than bromides and iodides. Give reason for your answer.
- 8View SolutionAryl chlorides and bromides can be easily prepared by electrophilic substitution of arenes with chlorine and bromine respectively in the presence of Lewis acid catalysts. But why does preparation of aryl iodides requires presence of an oxidising agent?
- 9View SolutionDraw the structures of major monohalo products in each of the following reaction:
- 10Name the following halides according to $\text{IUPAC}$ system and classify them as alkyl, allyl, benzyl $($primary, secondary, tertiary$),$ vinyl or aryl halides:View Solution
$\ce{CH_3CH=C(Cl)CH_2CH(CH_3)_2}.$