Question
Write the logarithmic equation for:$E=\frac{1}{2} m v^2$

Answer

$E =\frac{1}{2} m v ^2$
Considering $\log$ on both the sides, we get
$\log E=\log \left(\frac{1}{2} mv^2\right)$
$=\log \frac{1}{2}+\log m+\log v^2 $
$=\log 1-\log 2+\log m+2 \log v $
$=\log m+2 \log v-\log 2$

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