Question
Write the supplement of 80° 49′ 25″

Answer

Supplement of $80^{\circ} 49^{\prime} 25^{\prime \prime}$
$ \begin{aligned} & =180^{\circ}-80^{\circ} 49^{\prime} 25^{\prime \prime} \\ & =99^{\circ} 10^{\prime} 35^{\prime \prime} \ldots . .\left\{\because 1^{\circ}=60 \prime \text { and } 1 \prime=60 \prime \prime\right\} \end{aligned} $

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