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MATHS [2 Mark Question Answer]

Lines and Angles (Including Construction of angles) · ICSE STD 7 (ICSE - English Medium). 15 questions.

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[2 Mark Question Answer]

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15 questions · timed · auto-graded

Question 12 Marks
Which pair of the dotted line, segments, in the following figure, are parallel. Give reason:

Answer
Lines are parallel
If alternate angles are equal
⇒ 50° = 40°
Which is not true lines are not parallel.
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Question 22 Marks
Which pair of the dotted line, segments, in the following figure, are parallel. Give reason:
Image
Answer
In figure,
Lines are parallel if corresponding angles are equal
If 120° =130° which is not correct
∴ Lines are not parallel.
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Question 32 Marks
Which pair of the dotted line, segments, in the following figure, are parallel. Give reason:
Image
Answer
In the figure, If lines are parallel, then 120°+ 50° =180°
But there are co-interior angles
⇒ 170° = 180°. But it not true Hence, there are not parallel lines
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Question 42 Marks
In the following figure, $\angle A O B$ and $\angle A O C$ are adjacent angles?
Give the reason for your answer.
Image
Answer
If ∠AOB and ∠AOC are adjacent angles if they have OA their common arm.
In this figure, OB is their common arm
∴ ∠AOB and ∠AOC are not adjacent angles.
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Question 52 Marks
In the following figure, $\angle A O B$ and $\angle A O C$ are adjacent angles?
Give the reason for your answer.
Answer
If ∠AOB and ∠AOC are adjacent angles if they have OA their common arm.
In this figure, OA is their common arm
∴ ∠AOB and ∠AOC are adjacent angles.
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Question 62 Marks
In the following figure, $\angle A O B$ and $\angle A O C$ are adjacent angles?
Give the reason for your answer.
Image
Answer
If ∠AOB and ∠AOC are adjacent angles if they have OA their common arm.
In the figure, OC is their common arm
∴ ∠AOB and ∠AOC also not adjacent angles.
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Question 72 Marks
In the following figure, $\angle A O B$ and $\angle A O C$ are adjacent angles?
Give the reason for your answer.
Image
Answer
If ∠AOB and ∠AOC are adjacent angles if they have OA their common arm.
In the figure, OB is their common arm
∴ ∠AOB and ∠AOC are not adjacent angles.
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Question 82 Marks
Are the following pairs of angles supplementary?
$\frac{3}{10}$ of a right angle and $\frac{4}{15}$ of two right angles.
Answer
$\frac{3}{10}$ of a right angle and $\frac{4}{15}$ of two right angles
$\Rightarrow \frac{3}{10}$ of $90^{\circ}$ and $\frac{1}{15}$ of $180^{\circ}$
$\Rightarrow 27^{\circ}$ and $48^{\circ}$
$\mathrm{No}$, there are not supplementary angles as their sum is not
$180^{\circ}\left(27^{\circ}+48^{\circ}=75^{\circ}\right)$
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Question 92 Marks
Are the following pairs of angles complementary?
$54^{\circ}$ and $\frac{2}{5}$ of a right angle.
Answer
$54^{\circ}$ and $\frac{2}{5}$ of a right angle
$ \begin{aligned} & \Rightarrow 54^{\circ} \text { and } \frac{2}{5} \times 90^{\circ} \\ & \Rightarrow 54^{\circ} \text { and } 36^{\circ} \end{aligned} $
Yes, there are complementary angles as their sum is
$90^{\circ}\left(54^{\circ}+36^{\circ}=90^{\circ}\right)$
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Question 102 Marks
Write the supplement of 80° 49′ 25″
Answer
Supplement of $80^{\circ} 49^{\prime} 25^{\prime \prime}$
$ \begin{aligned} & =180^{\circ}-80^{\circ} 49^{\prime} 25^{\prime \prime} \\ & =99^{\circ} 10^{\prime} 35^{\prime \prime} \ldots . .\left\{\because 1^{\circ}=60 \prime \text { and } 1 \prime=60 \prime \prime\right\} \end{aligned} $
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Question 112 Marks
Write the supplement of (110 – x – 2y)°
Answer
Supplement of (110 − x − 2y)°
= 180°− (110 − x − 2y)°
= 180°− 110° + x°+ 2y°
= 70° + x° + 2y°
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Question 122 Marks
Write the supplement of (x + 35)°
Answer
Supplement of (x + 35)°
= 180°− (x + 35)°
= 180°− x°− 35°
= 145°− x°
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Question 132 Marks
Write the complement of $\frac{1}{3}$ of $180^{\circ}$
Answer
Complement of $\frac{1}{3}$ of $180^{\circ}$
$ \begin{aligned} & =90^{\circ}-\frac{1}{3} \text { of } 180^{\circ} \\ & =90^{\circ}-60^{\circ}=30^{\circ} \end{aligned} $
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Question 142 Marks
Write the complement of $\frac{1}{2}$ of a right angle
Answer
Complement of $\frac{1}{2}$ of a right angle
$=90^{\circ}-\frac{1}{2}$ right angle
$ \begin{aligned} & =90^{\circ}-\frac{1}{2} \times 90^{\circ} \\ & =90^{\circ}-45^{\circ}=45^{\circ} \end{aligned} $
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Question 152 Marks
Write the complement of (30 − a)°
Answer
Complement of (30 − a)°
= 90°− (30 − a)°
= 90°− 30° + a° = 60° + a°
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[2 Mark Question Answer] - MATHS STD 7 Questions - Vidyadip