MCQ
$x d x+\frac{x d y-y d x}{x^2+y^2}=0$ का हल है :
  • A
    $\frac{x^2}{2}+\tan ^{-1} \frac{x}{y}=k$
  • $\frac{x^2}{2}+\tan ^{-1} \frac{y}{x}=k$
  • C
    $\frac{x^2}{2}-\tan ^{-1} \frac{x}{y}=k$
  • D
    $\frac{x^2}{2}-\tan ^{-1} \frac{y}{x}=k$

Answer

Correct option: B.
$\frac{x^2}{2}+\tan ^{-1} \frac{y}{x}=k$
(B)

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