MCQ
$X$ in the above reaction is


- A$HN{O_3}$
- B${O_2}$
- C${O_3}$
- ✓$KMn{O_4}$


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$(I)$ electron affinity of $Y$ is high $(II)$ ionization energy of $X$ is low
$(III)$ lattice energy of $XY$ is high $(IV)$ lattice energy of $XY$ is low
Choose the correct code
${C_6}{H_6}(l)\, + \,\frac{{15}}{2}\,{O_2}(g)\, \to \,6\,C{O_2}(g)\, + \,3{H_2}O\,(g)$
Signs of $\Delta H,\,\Delta S$ and $\Delta G$ for the above reaction will be
($A$) tetranuclear $\left[\mathrm{B}_4 \mathrm{O}_5(\mathrm{OH})_4\right]^{2-}$ unit
($B$) all boron atoms in the same plane
($C$) equal number of $s p^2$ and $s p^3$ hybridized boron atoms
($D$) one terminal hydroxide per boron atom