MCQ
${x^2} - 4{y^2} - 2x + 16y - 40 = 0$ represents
- AA pair of straight lines
- BAn ellipse
- ✓A hyperbola
- DA parabola
==> $({x^2} - 2x) - 4({y^2} - 4y) - 40 = 0$
==> ${(x - 1)^2} - 1 - 4[{(y - 2)^2} - 4] - 40 = 0$
==> ${(x - 1)^2} - 4{(y - 2)^2} = 25$
==> $\frac{{{{(x - 1)}^2}}}{{25}} - \frac{{{{(y - 2)}^2}}}{{25/4}} = 1$, which is a hyperbola.
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.