MCQ
$XeF_{2(g)} + H_{2(g)} \to 2HF_{(g)} + Xe_{(g)}\, \Delta H^o = -430\, kJ$
Bond energy $\to H-H = 435\, kJ/mol$

                     $\to H-F = 565\, kJ/mol$
Calculate average bond energy of $Xe-F$ bond.....$ kJ/mol$

  • A
    $265$
  • B
    $562.5$
  • $132.5$
  • D
    None of these

Answer

Correct option: C.
$132.5$
c
$\Delta_{\mathrm{r}} \mathrm{H}=(2 \mathrm{X}+435)-2(565)$

$-430=435+2 X-1130$

$\mathrm{X}=132.5 \,\mathrm{kJ} / \mathrm{mol}$

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