Xe F_4 on partial hydrolysis produces - Vidyadip

MCQ

$Xe{F_4}$ on partial hydrolysis produces

A
$Xe{F_2}$
✓
$XeO{F_2}$
C
$XeO{F_4}$
D
$Xe{O_3}$

✓

Answer

Correct option: B.

$XeO{F_2}$

b
(b) Partial hydrolysis; $Xe{F_4} + {H_2}O \to $$XeO{F_2} + 2HF$

Complete hydrolysis;

$2Xe{F_4} + 3{H_2}O\, \to $$Xe + Xe{O_3} + {F_2} + 6HF$

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$\begin{matrix}
O\,\,\, \\
||\,\,\, \\
C{{H}_{3}}-C-C{{H}_{2}}- \\
\end{matrix}\begin{matrix}
O\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, \\
||\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, \\
C{{H}_{2}}-C-C{{H}_{3}}\xrightarrow[\Delta ]{{{(N{{H}_{4}})}_{2}}C{{O}_{3}}}\xrightarrow[\Delta ]{CC{{l}_{3}}C{{O}_{2}}Na}\underset{(major)}{\mathop{(B)}}\, \\
\end{matrix}$

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