- A$XeOF_4$
- B$XeO_2F_2$
- ✓$XeO_3$
- D$XeO_2$
$XeF_6 + 3H_2O \to XeO_3 + 6HF$
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$6 OH ^{-}+ Cl ^{-} \rightarrow ClO _{3}^{-}+3 H _{2} O +6 e ^{-}$
If only $60 \%$ of the current is utilized in the reaction, the time (rounded to the nearest hour) required to produce $10\, g$ of $KCIO _{3}$ using a current of $2\, A$ is..........
(Given : $F =96,500\, C\, mol ^{-1}$ molar mass of $\left. KClO _{3}=122\,gmol ^{-1}\right)$
$E^o_{Cr^{3+}/Cr} =-0.74\, V,\,$ $E^o_{MnO_4^-/Mn^{2+}} =1.51 \,V$
$E^o_{Cr_2O_7^{2-}/Cr^3+} =1.33\,V:$ $E^o_{Cl/Cl^-} =1.36\,V$
Based on the data given above, strongest oxidising agent will be :
The order of decreasing reactivities of these alcohols towards nucleophilic substitution with $HBr$ is